WebAug 31, 2015 · Your idea is right but you need HAVING COUNT(DISTINCT design) > 1. Like this: WITH multi_design_perfs AS (SELECT b.perf_id FROM perf_ticket_type b GROUP BY b.perf_id HAVING COUNT(DISTINCT b.design) > 1 ) SELECT m.perf_id, STUFF((select ', ' + CAST(b.design AS varchar(10)) FROM perf_ticket_type b WHERE b.perf_id = m.perf_id … WebMay 15, 2011 · Answers. 1. Sign in to vote. You are close to the final solution. There are three operations involved with pivoting data, grouping (GROUP BY), spreading (CASE …
. Write SQL commands to answer the following queries: You...
Web17 hours ago · Numeric value is not recognized SQL. I have below table called "inspection" and schema called "raw" . Both column Boro, Inspection_date are varchar. I am trying to do transformation and save in new schema called "curated" and table name called "insp". WebDec 17, 2024 · I would like to group by my table on values 1,2,3,4,5 so I have created a temporary table with this values. ... Conversion failed when converting the varchar value 'simple, ' to data type int. (on line 7) ... tsql. group-by. how do you treat halitosis
SQL varchar data type deep dive - SQL Shack
Web我永遠不會使用 distinct 但總是制定 group by 子句,distinct 實際上是一個臟組,因為 output ... PRIMARY KEY, ACCT VARCHAR(10) NOT NULL, DOC VARCHAR(10) NOT NULL, GENDER VARCHAR(10) NULL) INSERT INTO @TableTest (ACCT, DOC , GENDER ... get first 3 comma separated values WebAug 13, 2024 · The first elements of both arrays are equal (1), so PostgreSQL moves on to the next element. In this case, the second element of the second array (201) is the greatest. Max by Key... Using this feature of PostgreSQL, we construct an array where the first element is the value to sort by, and the second element is the value we want to keep. WebJul 19, 2014 · Note: This answer is intended as a supplement to @Lukas Eder's answer. If there are multiple values present for the fields SELECTed but a field you wish to GROUP BY, you could instead grab the top matching line, rather than waiting for an aggregation (MAX) to return.. SELECT i.RoleName, i.* FROM Rls JOIN (SELECT TOP 1 R.Rolename, … phonic am440